Help
Sign In »
Register Now!
hello,
I'd like to know how does the solar radiation received on a flat surface vary if we change the angle of it.
To simplify, if I've got a board of 1*1meters (at 0º -parallel to the ground-) and it is receiving 1Kw/h, the sun being at 90º, how will it received if I turn it 10º?
Thank you
Jaime
Welcome to ScienceForums.Net!
|
Welcome to ScienceForums.Net! We welcome science discussion at all levels — from beginners to researchers, covering topics from biology to computer science, and much more. Registration is fast and free, and allows you to post on the forums, so register now and join the discussions! After you've registered, come in and introduce yourself, or visit the forum index. If you need any help registering, posting, or if you just have some questions about our site, please feel free to contact us at staff at scienceforums dot net.
|
|
| Guest Message © 2012 DevFuse | |
Page 1 of 1
amount of radiation received dependng on angle
Rate Topic:
#2
7 January 2012 - 01:53 PM
John Cuthber 
Chemistry Expert
You move it so the sun hits it at 80 degrees rather than 90.
Sin(80º) is 0.9848
It will receive roughly 985W.
There is another factor- more of the light will be reflected from the steeply sloping surface so the efficiency drops more rapidly than the simple geometry would suggest.
That factor depends on the material from which the cell is made etc- it's rather difficult to calculate. If I were you, I would ask the manufacturer how the angle affects the energy output.
Sin(80º) is 0.9848
It will receive roughly 985W.
There is another factor- more of the light will be reflected from the steeply sloping surface so the efficiency drops more rapidly than the simple geometry would suggest.
That factor depends on the material from which the cell is made etc- it's rather difficult to calculate. If I were you, I would ask the manufacturer how the angle affects the energy output.
What's this signature thingy then? Did you know Santa only brings presents to people who click the + sign? -->
- Posts: 4,895 | Joined: 24-February 06
Reply
#4
8 January 2012 - 10:09 PM
swansont
Shaken, not Stirred
jc.int, on 8 January 2012 - 08:31 PM, said:
Thank you for your reply,
can you explain me why do you use the sine of the angle?
Jaime
can you explain me why do you use the sine of the angle?
Jaime
It's the projection of the area onto the perpendicular surface. Draw the triangle and you can see it's the sine.
Minutus cantorum, minutus balorum, minutus carborata descendum pantorum
Stop failing the Turing test!
My SFN blog: Swans on Tea
To release the hounds, click the [+] sign ->
Stop failing the Turing test!
My SFN blog: Swans on Tea
To release the hounds, click the [+] sign ->
- Posts: 19,649 | Joined: 04-October 03
- Reply
#5
9 January 2012 - 11:25 AM
jc.int
Lepton
In this case, wouldn'y it be the cosine? If you look at this graph, where [BC] is the board, it seems that the projection of the area onto the perpendicular surface is the cosine,isn't it?
Attached thumbnail(s)
This post has been edited by jc.int: 9 January 2012 - 11:28 AM
- Posts: 6 | Joined: 29-December 11
- Reply
#6
9 January 2012 - 11:29 AM
swansont
Shaken, not Stirred
I can't view the image, but it would probably be the other angle, since sin(80) = cos(10). John used the large angle, and I'm guessing you are looking at the small angle.
Minutus cantorum, minutus balorum, minutus carborata descendum pantorum
Stop failing the Turing test!
My SFN blog: Swans on Tea
To release the hounds, click the [+] sign ->
Stop failing the Turing test!
My SFN blog: Swans on Tea
To release the hounds, click the [+] sign ->
- Posts: 19,649 | Joined: 04-October 03
- Reply
Share this topic:
Page 1 of 1