[Santosh Choudhury]

How can I Dilute HCL from any concentrate HCL to any diluted HCL. e.g 38% HCL to 10% HCL. Is there any formula for HCL Dilution...?

[insane_alien]

just use the basic dilution formula:

C1V1=C2V2

where C denotes concentration, V denotes volume 1 denotes initial condition and 2 denotes final concentration.

rearrange to suit the situation.

[skwiff]

work out (or just google it) the molaraty of 38% HCl (should be about 12 or 13 moles) using the following n=m/RMM and then use this to work out the concentration C=n/V

[pippo]

skwiff, on 7 October 2011 - 02:20 PM, said:

work out (or just google it) the molaraty of 38% HCl (should be about 12 or 13 moles) using the following n=m/RMM and then use this to work out the concentration C=n/V

Right, but diluting it to your desired 10% HCl does not indicate the molarity- only way to find it is to consult tables. 10% w/w HCl is 100g HCl per 1000grams, not 1000mls. You cant know the molarity unless you know how many mls the 1000g of the 10% will be. tables is it.

This post has been edited by pippo: 23 November 2011 - 11:55 PM

[mskittykat]

38% HCl is about 12M. That's standard concentrated acid that is commercially available.

if you want 10% of this HCl, usually it's just 100mL HCl and 900mL DI water... This gets you down to
about 1 L of 1.2 M HCl.

The formula used is C1V1 = C2V2.
C1= concentration initial
V1 = how much of initial used
C2 = concentration final (what you want to end up with)
V2 = Volume you want to end up with

Remember, C and V has to be in the same units on both sides

Santosh Choudhury, on 27 July 2011 - 07:54 PM, said:

How can I Dilute HCL from any concentrate HCL to any diluted HCL. e.g 38% HCL to 10% HCL. Is there any formula for HCL Dilution...?

[pippo]

The OP did not indicate if he meant 10% v/v or 10% w/w, or even w/v, or a Normality (molarity) value. There is a huge difference. It can not be said how to do this dilution unless he specifies the units. Assuming otherwise shows lack of laboratory and manufacturing, and assaying experience.

just the same, he is long gone from a July posting.....on to another thread.

[John Cuthber]

"The OP did not indicate if he meant 10% v/v or 10% w/w, or even w/v, or a Normality (molarity) value. "
Actually, he did, albeit tacitly.

[pippo]

John Cuthber, on 3 December 2011 - 04:10 PM, said:

"The OP did not indicate if he meant 10% v/v or 10% w/w, or even w/v, or a Normality (molarity) value. "
Actually, he did, albeit tacitly.

John,

although the OP is gone by now, for the record, one shouldnt perform any chem work tacidly......lol. I hope you dont either.

I felt he was not clear as to what he even wanted. That was the reason for my detailed units explanation/clarification. That is my kind of chemistry, and if I had to approach doing this also for a living tacidly, I would only be helping my competition, right?

[insane_alien]

even so, C1V1=C2V2 will still apply assuming the particulars of the percentages on either side are consistent with each other.

[John Cuthber]

pippo, on 7 December 2011 - 01:22 AM, said:

John,

although the OP is gone by now, for the record, one shouldnt perform any chem work tacidly......lol. I hope you dont either.

I felt he was not clear as to what he even wanted. That was the reason for my detailed units explanation/clarification. That is my kind of chemistry, and if I had to approach doing this also for a living tacidly, I would only be helping my competition, right?

If I had written "tacidly" that might have been relevant.