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At what redshift does energy density of matter = energy density of radiation? Rate Topic: -----

#1 zeion 


Lepton
Hello. This is question for my course work, I was wondering if I could get some insight, here is the question:

Assume that the vast majority of the photons in the present Universe are cosmic microwave radiation photons that are a relic of the big bang. For simplicity, also assume that all the photons have the energy corresponding to the wavelength of the peak of a 2.73K black-body radiation curve. At Approximately what redshift will the energy density in radiation be equal to the energy density in matter?

(hint: work out the energy density in photons at the present time. Then work it out for baryons, assuming a proton for a typical baryon. Remember how the two quantities scale with redshift to work out when the energy density is the same.)


 \rho_M \propto a^{-3}

\rho_\gamma \propto a^{-4}

T \propto a^{-1}

1 + z = \frac{v}{v_0} = \frac{\lambda_0}{\lambda} = \frac{a(t_0)}{a(t)}

How do I calculate the energy density of photons and protons at the present time? Do I use E = mc^2?
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#2 Radical Edward 


Primate
what are your variables there? It's been a while since I worked with that sort of stuff. lambda I guess is wavelength, v, velocity, t and to are time, rhos are density, but what about a and z?
The Ancient
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#3 zeion 


Lepton
a is the scale factor for the size of the universe where the a = 1 at the present time.. and 0.5 sometime in the past when it was half the size, etc.. and z is the redshift.
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