Jump to content


Photo
- - - - -

Combustion of Heptane


  • Please log in to reply
2 replies to this topic

#1 foolishone

foolishone

    Quark

  • Members
  • 16 posts

Posted 5 February 2008 - 04:06 AM

Hi all,

I have been tasked with finding the equation for the combustion of heptane (C7H16).

We put some heptane on a watch glass and watched it burn and it disappeared. I am assuming that it reacted with the air, or the moisture in it. Does it evaporating rather quickly on the watch glass point to something obvious?

Can someone point me in the right direction?

All questions and comments are appreciated.

Thanks!

»fo


EDIT:

Something like this...???

C7H16 + 11(O2) == 7(CO2) + 8(H2O)
  • 0

#2 CaptainPanic

CaptainPanic

    Usually himself

  • Moderators
  • 4,732 posts
  • LocationThe little swamp at the end of the river Rhine

Posted 5 February 2008 - 09:55 AM

The reaction you wrote down is correct.

The heptane reacted with air, not with moisture. Actually, it reacted only with the oxygen (O2) from air. The other compounds in air, such as nitrogen (N2), don't do much. Moisture is a product from the reaction. Moisture (water) is H2O that is formed.

About the evaporation: when it burned it created heat. This heat made it evaporate faster. (It's like water: it evaporates a lot faster on a hot summer's day than in winter).
  • 0

#3 YT2095

YT2095

    Chemistry Expert

  • Resident Experts
  • 16,959 posts

Posted 5 February 2008 - 10:15 AM

the Heat of the enthalpy change is enough to overcome the Van de walls forces keeping the individual molecules together.

so they "Evaporate".
  • 0




0 user(s) are reading this topic

0 members, 0 guests, 0 anonymous users