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Pulling my donkey


countSpanky

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I suck at physics. Newtonian law specifically...

 

2 guys are pulling a donkey; one from an angle of 80° at 80N, the other from an angle of 75° at 120N. What is the resulting force?

 

Result isn't important, just the steps of getting there.

 

Gracias!

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Alright, well you have two forces, both acting on the X and Y axis.

 

F1 = 80N, :theta:1 = 80'

 

F2 = 120N; :theta:2 = 75'

 

Now what you want to do is find the sum of all forces for each coordinate (x and y)

 

:sum:Fx = 80cos(80) + 120cos(75)

 

That will give you the x-vector of both forces. Do the same for the Y-vector..

 

:sum:Fy = 80sin(80) + 120sin(75)

 

(if you don't know why to use sin and cos, let me know)

 

Now you have the sum of forces on the X and Y axis.

 

To add the vectors, you must find the hypotenuse of the vector diagram. The hypotenuse will be your final sum of all forces

 

Using a^2 + b^2 = c^2:

 

c = sqrt(Fx^2 + Fy^2)

 

That will be your final answer.

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