Garfield Posted November 12, 2005 Share Posted November 12, 2005 This is a simple exercise but I can't solve it... A 10m 9000N beam is risen up by two parallel wire ropes (a=0m/s^2), one attached to one end and the other 1m from the other end. At what force each wire rope is rising the beam? Sorry for the broken English. Link to comment Share on other sites More sharing options...
swansont Posted November 12, 2005 Share Posted November 12, 2005 What is the net force on the beam? What are all the forces on the beam? It usually helps to draw a free-body diagram for these problems. Link to comment Share on other sites More sharing options...
Garfield Posted November 13, 2005 Author Share Posted November 13, 2005 [math]F_{net} = 0N[/math] because [math]a = 0ms^{-2}[/math], the forces on the beam are [math]F_{grav}=-(F_{rope1}+F_{rope2})=9000N[/math], and the free-body diagram didn't help me either. I'm awful in physics but if someone could give me more hints... Link to comment Share on other sites More sharing options...
Severian Posted November 13, 2005 Share Posted November 13, 2005 What does the fact that the beam is not turning as it is raised tell you? Link to comment Share on other sites More sharing options...
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