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Assistance on Physics experiment. Please help


youngvuth

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I met , the time is relative to the object falling in vacuum.

 

 

 

Still not making much sense.

 

There is no obvious relationship between the rate of fall in a vacuum and in a medium where the terminal velocity becomes significant.

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  • 5 weeks later...

We know the fact that force due to gravity is F1=GMm/r^2

 

Now subtract your constant air drag from it, say F2

 

The net force is

F=F1-F2

=GMm/r^2 - F2

 

Now to get acceleration , divide by m

 

a = GM/r^2 - F2/m

 

This is dependent upon mass

 

Heavier the mass, less retarding effect, faster the object falls down.

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The air resistance is not a constant. For identical shapes the drag will be proportional to the square of the velocity, assuming the coefficient of drag does not change. If it does you must factor that in. The only point where the velocity will be the same is at the start, when dropped. The lighter object will otherwise accelerate more slowly but reach it's terminal velocity earlier, at a lower velocity.

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