thecavswillchoke35 Posted April 19, 2017 Share Posted April 19, 2017 sorry had to put up another question, im pretty sure that the higher the kc, the more the products are formedand so I can cancel out C but im not sure about the otherscheers Link to comment Share on other sites More sharing options...
hypervalent_iodine Posted April 19, 2017 Share Posted April 19, 2017 Are you familiar with calculating reaction quotients (Q)? Link to comment Share on other sites More sharing options...
thecavswillchoke35 Posted April 19, 2017 Author Share Posted April 19, 2017 u mean " delta g = delta g (standard) + RTlnQ"? Link to comment Share on other sites More sharing options...
hypervalent_iodine Posted April 19, 2017 Share Posted April 19, 2017 No. Q in that equation is the same thing, but I don't mean that equation. It is calculated in exactly the same way as K, but it does not matter if the concentrations of each species is at equilibrium. The point of the calculation is to determine whether or not Q = K, and thus whether or not the system is at equilibrium. Whether or not Q is less than, greater than, or equal to K will tell you if it's at equilibrium, or if not, which direction it will go to reach equilibrium. 1 Link to comment Share on other sites More sharing options...
thecavswillchoke35 Posted April 20, 2017 Author Share Posted April 20, 2017 No. Q in that equation is the same thing, but I don't mean that equation. It is calculated in exactly the same way as K, but it does not matter if the concentrations of each species is at equilibrium. The point of the calculation is to determine whether or not Q = K, and thus whether or not the system is at equilibrium. Whether or not Q is less than, greater than, or equal to K will tell you if it's at equilibrium, or if not, which direction it will go to reach equilibrium. thanks i get it now Link to comment Share on other sites More sharing options...
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