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lila

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  1. it usually the BH3 -THF is generated by using NaBH4/I2 and many papers confirmed this method give only one enantiomer....so I was trying to know the transition state which lead to this enantioselectivity.
  2. thanks but how the control in enantioselectivity during the transition state. I think the mechanism is still unclear. thankssssss
  3. Please I need the detallied mechanism of the reduction of carboxylic acids using BH3-THF ? Thanks for any help
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