ok so i want to know if there is an easier way to figure out how many times you would have to double a number before getting to certain number. (other then going 2x2x2x2x2x2x2
question two lets say we take the number 1080 is there a way to figure out how many times it had been doubled assuming the start point is 1
what if the starting number was 4 any way to figure that out besides the long way
and this is not homework, i was just folding a piece of metal on itself over and over (like Damascus steel but i used indium since its soft and doesn't require heat to get the layers to bond but it also doesnt add any strength i just wanted to see how many layers i could get. unfortunately my computer needed a reboot and i forgot to write down the number it was roughly 3.8^43 layers ) so each time i fold it the number of layers doubles, so it got me thinking about
interesting not about the number of layers in the indium, the indium was 0.8mm thick so based on those numbers i believe each layer would be thinner then an atom which i know it isnt possible to have layers thinner then the atoms in those layers. it like the thing one of my teachers said about if ia guy was waolking across the road but could only do it in halves (so at first he woud be in the middle of the road second he would be 3/4 of the way across...and so on. but he could never make it across the road. obviously not realistic the teacher made his point) but i did this like 6 months ago so i might have scred up the math on how many indium atoms thick 0.8mm would be. but am positive it was 3.8 to the 43rd