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soccer022483
April 17th, 2004, 12:31 PM
Can anyone prove this?

If Tau(n) is an odd integer, then n is a perfect squre

Thanks,
Austin

jordan
April 17th, 2004, 3:34 PM
Mabey I'm missing something, but is there any specific relationship between n and tau in this?

AntiMagicMan
April 18th, 2004, 10:13 AM
The tau I know of is the one such that tau(n) = the number of positive divisors of n.

dave
April 18th, 2004, 10:50 AM
From wolfram:

http://mathworld.wolfram.com/TauFunction.html

Although I have no idea as to how to solve the problem :-)

AntiMagicMan
April 18th, 2004, 12:18 PM
Hmm, mathworld seems to define the tau slightly differently to the one I know. Though I think the original conjecture is true only for my definition of tau, something that mathworld calls sigma.

Either i'm missing something really basic, but it seems like a hard proof. I'll have a look through my algebra books.