need help!!!

[Dumass]

hi can anyone here help me solve this??? :confused:

[wolfson]

What was the question?, if unsure which variable do you want me to relate to??

[Dumass]

i'm from another forum & a member has posted this problem. i have no idea what it is or what it's asking for.
any info. or input will be helpful

[VendingMenace]

hmm...it appears to be as wolfson says. There doesn't really seem to be a question. What forum are you from, if you give us a link to the original post, perhaps that would shed some light on it?

[Dudde]

as I was too hurried to say earlier when I saw this, and these two have just stated, there is no question

give a link

please

[Dumass]

i copied the problem from the posting..
oh btw it's not from a math/science forum... just a motorcycle forum... some one must have dug into his text book or something

http://www.r1-forum.com/forums/showthread.php?s=&threadid=55773&perpage=20&pagenumber=1

[wolfson]

E = sqrt( p^2c^2 + m^2c^4)

E=f(m, p))
SR:-
E = sqrt( p^2c^2 + m^2c^4)
if
E=mc^2 (m > 0 & p = 0) and
E=pc (m = 0 & p > 0).

Let E = f(m, p), where
f(m,p)
=mc^2 (m > 0 & p = 0)
=pc (m = 0 & p > 0)
= '?' ( m > 0 & p > 0)
E=G^2=c^2

m = sqrt(c'/c)*m

dimension of mc2 is [ M ][ L ]2/[ T ]2

These are preliminary answers I have worked, but I will have to study for a bit longer to contribute L^T.

[wolfson]

I think the idea is that when E >> p the general formula for the energyof a particle with mass m and momentum p.

E = (m^2 + p^2)^(1/2)

can be approximated by keeping just the first two terms in the
expansion


E = p + m^2/2p + ...


If you kept only the leading term in the expansion you would have
E = p,
which corresponds to a particle that travels at the speed of light.