gez
July 6th, 2003, 5:47 AM
Can you arrange the digits 1,2,3,4,5,6,7,8,9
in an order so that the number formed by the first number formed by the first 2 digits is divisible by 2. First 3 digits
divisible by 3. First four digits is divisible by 4 and the first 5
digits is divisible by 5 and so on up to nine digits?
12 is divisible by 2, 123 is divisible by 3, 1236 is divisible by 4,
12365 is divisible by 5, 123654 is divisible by 6 but 1236549 is not divided by 7! :-( :rolleyes:
i hope you can help thankz!
in an order so that the number formed by the first number formed by the first 2 digits is divisible by 2. First 3 digits
divisible by 3. First four digits is divisible by 4 and the first 5
digits is divisible by 5 and so on up to nine digits?
12 is divisible by 2, 123 is divisible by 3, 1236 is divisible by 4,
12365 is divisible by 5, 123654 is divisible by 6 but 1236549 is not divided by 7! :-( :rolleyes:
i hope you can help thankz!